The total resistance of the section of the circuit, consisting of two resistors connected in parallel, R = 40 ohms. Determine the resistance of the first resistor R1, if the resistance of the second R2 = 200 ohms?
Initial data: R (total resistance of the circuit section) = 40 Ohm; R2 (resistance of the second resistor) = 200 Ohm; the circuit section consists of two resistors connected in parallel.
The resistance of the first resistor is determined from the formula: 1 / R = 1 / R1 + 1 / R2.
1/40 = 1 / R1 + 1/200.
1 / R1 = 1/40 – 1/200 = 4/200.
R1 = 200/4 = 50 ohms.
Answer: The resistance of the second resistor is 50 ohms.
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