# The trailer is detached from the vehicle, which is traveling at a constant speed.

The trailer is detached from the vehicle, which is traveling at a constant speed. It is known that before its full stop, the trailer, moving with equal slowness, traveled 200 m. Determine the distance that the car has traveled during this time.

V = 0 m / s.

Sп = 200 m.

Sa -?

The movement of the trailer Sп to a full stop will be determined by the formula: Sп = V0 ^ 2/2 * a, where V0 is the speed of the trailer at the moment of uncoupling, and is the acceleration of the trailer.

Let us express the acceleration of the trailer a: a = V0 / t.

Sп = V0 ^ 2 * t / 2 * V0 = V0 * t / 2.

Let us express the travel time of the trailer t until a complete stop: t = 2 * Sп / V0.

Let us find the distance Sа, which the car drove, moving uniformly with the speed V0 and time t.

Sa = V0 * t = V0 * 2 * Sп / V0 = 2 * Sп.

Sa = 2 * 200 m = 400 m.

Answer: the car has traveled the distance Sa = 400 m.

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