# The train approaches the station at a speed of 36 km / h and stops a minute after the start of braking.

March 31, 2021 | education

| **The train approaches the station at a speed of 36 km / h and stops a minute after the start of braking. With what acceleration did the train move?**

Train speed:

V = V0 + a * t, where V is the final speed of the train (V = 0 m / s), V0 is the initial speed of the train before braking (V0 = 36 km / h = 36 * 1000/3600 = 10 m / s), a – train acceleration (m / s²), t – train deceleration time (t = 1 min = 60 s).

Let us express and calculate the acceleration of the train when braking:

V = V0 + a * t.

0 = 10 + a * 60.

-10 = a * 60.

a = -10 / 60 = -10 / 60 = -0.17 m / s².

Answer: The train was moving with an acceleration of -0.17 m / s².