The train car, moving uniformly and in a straight line with a speed module of V1 = 72 km / h, was pierced by a bullet, the speed module of which is V2 = 750 m / s. If the width of the carriage is L = 3m, and the bullet velocity is constant perpendicular to the direction of movement of the carriage, then the holes in the opposite walls of the carriage will be displaced by a distance l equal to ….
According to the conditions of the problem, we have:
v1 = 72 km / h = 20 m / s – car speed;
v2 = 750 m / s – bullet speed;
L = 3 m – the width of the car.
It is required to find the displacement l in the holes that the bullet will pierce.
First, let’s find the time it takes for the bullet to fly the carriage:
t = L / v2 = 3/750 = 0.004 m.
During this time t, the car will move to a distance l:
l = v1 * t = 20 * 0.004 = 0.08 m.
Answer: the offset of the holes in the opposite walls of the carriage is 0.08 meters (8 centimeters).
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