# The train was moving at a speed of 36 km / h (10 m / s) and began to slow down to a stop

August 29, 2021 | education

| **The train was moving at a speed of 36 km / h (10 m / s) and began to slow down to a stop of 100 meters. Find the time and the acceleration of the train.**

Given: V0 (train speed before braking) = 10 m / s; S (distance traveled to a complete stop) = 100 m.

1) Determine the modulus of acceleration of a given train during braking: S = V0 ^ 2 / 2a, whence a = V0 ^ 2 / 2S = 10 ^ 2 / (2 * 100) = 0.5 m / s2.

2) Let’s calculate the braking time: t = V0 / a = 10 / 0.5 = 20 s.

Answer: The deceleration of a given train lasted for 20 s with an acceleration of 0.5 m / s2.

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