The train went for one hour at a speed of 20 m / s, then for another 3 hours at a speed of 36

| March 31, 2021 | education

The train went for one hour at a speed of 20 m / s, then for another 3 hours at a speed of 36 km / h, and the length of the last section of the track was 20 km. What was the train route?

t1 = 1 h = 3600 s.

V1 = 20 m / s.

t2 = 3 h = 10800 s.

V2 = 36 km / h = 10 m / s.

S3 = 20 km = 20,000 m.

S -?

The entire path S traveled by the train will be the sum: S = S1 + S2 + S3.

The path S traveled by the train with uniform rectilinear movement is determined by the formula: S = V * t, where V is the speed of movement, t is the time of movement.

The traversed path on the first part of the path S1 is expressed by the formula: S1 = V1 * t1.

The traversed path on the second part of the path S2 is expressed by the formula: S2 = V2 * t2.

S = V1 * t1 + V2 * t2 + S3.

S = 20 m / s * 3600 s + 10 m / s * 10800 s + 20,000 m = 200,000 m = 200 km.

Answer: the train traveled the path S = 200,000 m = 200 km.



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