# The two spring pendulums have springs with an elasticity ratio (k1 / k2 = 4).

The two spring pendulums have springs with an elasticity ratio (k1 / k2 = 4). The ratio of the mass of the goods (m1 / m2 = 1). What will be the ratio of the oscillation periods?

The oscillation period of the spring pendulum:

T = 2Π * √ (m / k), where m is the mass of the suspended load, k is the spring stiffness of the pendulum.

From the ratio: k1 / k2 = 4; k1 = 4k2; m1 / m2 = 1; m1 = m2.

First spring pendulum:

T1 = 2Π * √ (m1 / k1) = 2Π * √ (m2 / 4k2).

Second spring pendulum:

T2 = 2Π * √ (m2 / k2).

The ratio of the periods of fluctuations:

Т1 / Т2 = 2Π * √ (m2 / 4k2) / 2Π * √ (m2 / k2) = 1/2 * 2Π * √ (m2 / k2) / 2Π * √ (m2 / k2) = 1/2.

Answer: The ratio of the periods of oscillations T1 / T2 = 1/2. One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.