The urn contains 10 blue and 6 green balls. 4 balls are chosen at random. What is the likelihood that they are all green?

There are 10 + 6 = 16 balls in the urn.
The probability of choosing the first green ball out of 16: p1 = 6/16.
The conditional probability of choosing the second green ball out of the remaining 15, provided that the green one is chosen first: p2 = 5/15.
The conditional probability of choosing the third green ball out of the remaining 14, provided that the first and second ones are green: p3 = 4/14.
The probability of choosing the fourth green ball is p4 = 3/13.
By the probability multiplication theorem, the probability of choosing all 4 green balls is:
P (4) = 6/16 5/15 4/14 3/13 = 0.00824.
Answer: The probability that all the selected balls are green is 0.00824.