The urn contains 8 white and 3 black balls. A white ball is taken out of the urn. After that, another ball is taken from the urn. Find the probability that he will be white too.
The first event only results in 7 white and 3 black balls remaining in the urn.
Therefore, the probability of event A that the second ball turns out to be white is equal to the ratio of the number of remaining white balls (7) to the total number of remaining balls (10):
P (A) = 7/10 = 0.7.
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