The voltage at the terminals of the electric vacuum cleaner is 220V, and the power consumption is 400W
The voltage at the terminals of the electric vacuum cleaner is 220V, and the power consumption is 400W. Determine the strength of the current passing through the electric motor and the resistance of its winding.
Given:
U = 220 Volts – voltage at the terminals of the electric motor;
W = 400 watts – the power consumed by the electric motor.
It is required to determine I (Ampere) – the current consumed by the electric motor, and R (Ohm) – the resistance of its winding.
Let’s find the current consumed by the electric motor:
I = W / U = 400/220 = 1.8 Amperes.
Then the resistance of the winding will be equal to:
R = U / I = 220 / 1.8 = 122 ohms (the result has been rounded to the nearest whole).
Answer: the current strength is 1.8 amperes, the resistance of the motor winding is 122 ohms.