The volume of 50% methanol solution (p = 0.64 g / ml) required for the interaction with 17.8 g

The volume of 50% methanol solution (p = 0.64 g / ml) required for the interaction with 17.8 g of aminopropionic acid.

Aminopropionic acid: CH3-CH (NH2) -COOH. Molecular formula: C3H7NO2. M = 89.09 g / mol.

Aminopropionic acid reacts with methanol to form an ester.

CH3-CH (NH2) -COOH + CH3OH = CH3-CH (NH2) -COOCH3 + H2O

n (amine acid) = m / M = 17.8 / 89.09 = 0.2 mol.

n (CH3OH) = n (amino acid) = 0.2 mol.

m (CH3OH) = n (CH3OH) * M = 0.2 * 32.04 = 6.4 g.

To get a 50% solution, you need to dilute the original solution 2 times.

m (50% p. CH3OH) = 6.4 * 2 = 12.8 g.

V (50% p. CH3OH) = m / p = 12.8 / 0.64 = 20 ml.