The volume of a piece of iron is 0.1 dm3. What buoyancy force will act on it when it is fully immersed in water; kerosene.

Initial data: V (volume of a piece of iron) = 0.1 dm3.

SI system: ρw (water density) = 1000 kg / m3; ρк (kerosene density) = 800 kg / m3; g (acceleration due to gravity) = 10 m / s2.

SI system: V = 0.1 dm3 = 0.1 * 10 ^ -3 m3.

1) Immersion in water: Fa1 = ρw * g * V = 1000 * 10 * 0.1 * 10 ^ -3 = 1 N.

2) Immersion in kerosene: Fa2 = ρк * g * V = 800 * 10 * 0.1 * 10 ^ -3 = 0.8 N.

Answer: When immersed in water, a buoyant force of 1 N acts on a piece of iron, and when immersed in kerosene – 0.8 N.



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