The weight of a simple mechanism and the friction in it are negligible. If using this mechanism we win 5 times in strength, then we … A) we lose 5 times in distance B) We win 5 times in distance C) we lose 25 times in distance D) We win 25 times in distance once
With regard to any simple mechanism, the following formula works: A = F * S, where F is the force applied to a certain point; S is the distance traveled.
1) Let the initial force be equal to F, then the work done by the mechanism is equal to A1 = F * S1.
2) After increasing the applied force by 5 times, substitute 5 * F into the work formula: A2 = 5 * F * S2.
3) If A1 = A2, F * S1 = 5 * F * S2.
4) From the formula we express S2 = F * S1 / 5 * F = S1 / 5.
That is, judging from the formula obtained, with an increase in force F by 5 times, the loss in distance is also 5 times.
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