The width of a rectangle is three-sevenths of its length, find its perimeter if the width is 24dm.

Given:

l = 24 dm;

l = (3/7) * L;

P -?

Solution:

Let’s find the length of the rectangle.

L * (3/7) = 24;

L = 24 / (3/7);

L = 24 * (7/3);

L = 56 dm.

Find the perimeter of the rectangle.

P = 2 * (L + l) = 2 * (56 + 24) = 2 * 80 = 160 dm.

Answer: the perimeter of the rectangle is 160 dm.



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