The width of the rectangle is 4 cm, which is 5 cm less than its length. Find the perimeter and area of this rectangle.

Solution:

1. Find the length of the rectangle:

4 + 5 = 9 (cm).

2. Find the perimeter of the rectangle:

P = 2 (a + b), side a is known to us from the conditions of the problem, side b we found in the first action.

P = 2 * (4 + 9) = 26 (cm).

3. Find the area of the rectangle:

S = ab;

S = 4 * 9 = 36 (cm 2).

Answer: the perimeter of the rectangle is 26 cm, the area is 36 cm 2 of the rectangle.