# The width of the rectangle is 8 m less than the length. Find the perimeter and area of the rectangle

March 27, 2021 | education

| **The width of the rectangle is 8 m less than the length. Find the perimeter and area of the rectangle if the width is 0.2 of the length.**

First of all, let’s calculate what the length and width are. Let’s designate the length as x meters, then the width is 0.2 meters. Knowing that the width is 8 meters less than the length, let’s create an equation.

x – 0.2x = 8;

0.8x = 8;

x = 8 / 0.8;

x = 10.

The length is 10 meters and the width is 0.2 * 10 = 2 meters.

Let’s find the value of the perimeter and area. To find the perimeter of a rectangle, you need to find the value of the doubled sum of the length and width. To find the area – the product of length and width.

P = 2 * (10 + 2) = 2 * 12 = 24 m.

S = 10 * 2 = 20 m².

Answer: 24 m, 20 m².

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