The width of the rectangle is 8 m less than the length. Find the perimeter and area of the rectangle

The width of the rectangle is 8 m less than the length. Find the perimeter and area of the rectangle if the width is 0.2 of the length.

First of all, let’s calculate what the length and width are. Let’s designate the length as x meters, then the width is 0.2 meters. Knowing that the width is 8 meters less than the length, let’s create an equation.

x – 0.2x = 8;

0.8x = 8;

x = 8 / 0.8;

x = 10.

The length is 10 meters and the width is 0.2 * 10 = 2 meters.

Let’s find the value of the perimeter and area. To find the perimeter of a rectangle, you need to find the value of the doubled sum of the length and width. To find the area – the product of length and width.

P = 2 * (10 + 2) = 2 * 12 = 24 m.

S = 10 * 2 = 20 m².

Answer: 24 m, 20 m².