There is a horse in the circus arena with a diameter of 12 meters.
There is a horse in the circus arena with a diameter of 12 meters. Determine the modulus of movement of the horse for 0.5 period of its movement.
D = 12 m.
t = T / 2.
The period of movement of the horse T is the time of one complete revolution of it around the arena.
Since the circus arena has the shape of a circle, after a time equal to t = T / 2 the horse will be on the opposite side of the circus arena.
The traversed path L is the length of the line that the body describes when moving. The horse, when moving, describes half the circumference: L = 2 * P * R / 2 = P * R = P * D / 2.
L = 3.14 * 12 m / 2 = 18.84 m.
The horse’s movement S is the vector that connects the horse’s starting and ending positions when moving. Since the horse was on the opposite side of the circle, then S = D.
S = 12 m.
Answer: the movement of the horse was S = 12 m, the path L = 18.84 m.