There is a skating rink on the highway section, the support area of which is 1500 cm². The pressure it produces is 30 N / cm². What is the weight of the roller?
S = 1500 cm2 = 0.15 m2.
P = 30 N / cm2 = 300000 N / m2.
The weight of the roller F is the force with which it pushes against the road surface.
The pressure of the roller P is the ratio of the force F to the area S on which this force acts: P = F / S. The roller acts on the highway by the force of its weight F.
The weight of the roller F is expressed by the formula: F = P * S.
F = 300,000 N / m2 * 0.15 m2 = 45,000 N.
Answer: the roller on the highway operates with a weight of F = 45000 N.
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