Three vessels contain 48 liters of water. If you pour 3 liters from the first vessel into the second

Three vessels contain 48 liters of water. If you pour 3 liters from the first vessel into the second, then the water in these two vessels will be equal, and if you pour 3 liters from the third vessel into the second, then the third will be 7 times less than in the second. How much water is in each vessel?

Let us denote by x liters the volume of liquid in the first container, and in the second by liters, then in the third there will be (48 – x – y) liters. We get:

x – 3 = y + 3,

((48 – x – y) – 3) * 7 = y + 3.

x = y + 3 + 3, x = y + 6.

((48 – y – 6 – y) – 3) * 7 = y + 3,

(39 – 2y) * 7 = y + 3,

273 – 14y = y + 3,

15y = 270,

y = 18.

x = 18 + 6 = 24 (l).

In the third container 48 – 18 – 24 = 6 (l).

Answer: from the first to the third vessel, respectively, 24 liters, 18 liters and 6 liters are poured.