# To 200 g of 5 ammonium chloride solution 15 g of the same salt and the same grams

To 200 g of 5 ammonium chloride solution 15 g of the same salt and the same grams of water were added. The mass fraction of ammonium chloride turned out to be

Let’s find the mass of salt and water in the original solution.

M salt 1 = 200.0 x 0.05 = 10.0 grams;

M water 1 = 200.0 – 10 = 190.0 grams;

Find the masses of salt in water in a solution after adding 15 grams of salt and 15 grams of water.

M salt 2 = 10 + 15 = 25 grams;

M water 2 = 190 + 15 = 205 grams;

The mass of the new solution will be:

M solution 2 = 25 + 205 = 230 grams;

Let’s find the mass fraction of ammonium chloride in the new solution:

With salt 2 = 25/230 = 0.109 = 10.9%;

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