To 300 g of a solution of barium chloride, a mass fraction of 20%, 200 ml of water was added. Determine the mass fraction in the resulting solution.
m (BaCl2 solution) = 300 g;
w% (BaCl2) = 20%;
V (H2O) = 200 ml;
% (BaCl2 in the final solution) -?
1) Find the mass of salt in the solution:
m (BaCl2) = 300 g * 0.2 = 60 g;
2) Find the mass of added water:
m (H2O) = p * V = 1 g / ml * 200 ml = 200 g;
3) Find the mass of the solution after adding water:
m (solution) = 300 g + 200 g = 500 g;
4) Find the mass fraction of salt in the solution:
w% (BaCl2) = m (BaCl2): m (solution) * 100% = 60 g: 500 g * 100% = 12%.
Answer: w% (BaCl2) = 12%.
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