To 300 liters of air was added 60 liters of nitrogen. Calculate the masses of oxygen and nitrogen
| September 14, 2021 | education
To 300 liters of air was added 60 liters of nitrogen. Calculate the masses of oxygen and nitrogen that can be obtained from this mixture.
Solution:
n (N₂) = V (N₂) / Vm
V (N₂) = 300 * 78/100 = 234 l + 60 = 294 l
V (0₂) = 300 * 21/100 = 62 l
m (N₂) = 28 * 294 / 22.4 = 367.5 g
m (О₂) = 32 * 62 / 22.4 = 88.6 g
Answer: 367.5 g, 88.6 g.
One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.
