To 300 liters of air was added 60 liters of nitrogen. Calculate the masses of oxygen and nitrogen

To 300 liters of air was added 60 liters of nitrogen. Calculate the masses of oxygen and nitrogen that can be obtained from this mixture.

Solution:

n (N₂) = V (N₂) / Vm

V (N₂) = 300 * 78/100 = 234 l + 60 = 294 l
V (0₂) = 300 * 21/100 = 62 l
m (N₂) = 28 * 294 / 22.4 = 367.5 g
m (О₂) = 32 * 62 / 22.4 = 88.6 g
Answer: 367.5 g, 88.6 g.




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