To 50 ml of 96% sulfuric acid (H2SO4) was added 250 ml of water (H2O). Calculate the omega of sulfuric acid in the resulting solution.
1) Find the mass of sulfuric acid. To do this, multiply the volume of acid by its density: 50 * 1.84 = 92g.
2) Find the mass of the solute of sulfuric acid in its solution. To do this, we multiply the mass fraction of the substance by the mass of the solution and divide by one hundred percent: 96 * 92/100 = 88.3 g.
3) Find the mass of water. We calculate similarly to point 1: 250 * 1 = 250g.
4) Find the mass of the solution after adding water: 92 + 250 = 342g.
5) Find the mass fraction (omega) of the acid in the resulting solution: 88.3 / 342 * 100 = 25.8% – the answer.
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