To an aqueous solution of chromium chloride (3) was added a solution of potassium sulfide.

To an aqueous solution of chromium chloride (3) was added a solution of potassium sulfide. This formed a greenish gelatinous precipitate of chromium hydroxide (3). Explain this phenomenon by writing the equation of salt hydrolysis.

The hydrolysis of potassium sulfide, as a salt formed by a strong base and a weak acid, will proceed along the anion (reaction 1 in the photo). The hydrolysis of chromium chloride, as a salt formed by a weak base and a strong acid, will go through the cation (reaction 2 in the photo). As a result, an excess of OH and H is formed in the solution. Therefore, hydrolysis continues further (reaction 3 in the photo). As a result, a precipitate of chromium hydroxide (greenish), hydrogen sulfide and potassium chloride are formed in the solution.
The overall reaction equation:
3K2S + 2CrCl3 + 6H2O = 2Cr (OH) 3 + 3H2S + 6KCl



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