# To melt 1 ton of scrap iron, taken at a temperature of 35, they spent 100 kg of coal.

**To melt 1 ton of scrap iron, taken at a temperature of 35, they spent 100 kg of coal. Determine the efficiency of the installation.**

To find out the required efficiency of the used installation, we use the formula: ηset = ml * (CFe * (tpl – t0) + λFe) / (qku * mku).

Const: СFe – beats. heat capacity of iron (СFe = 452 J / (kg * K)); tmelt is the melting point of iron (tmelt = 1538.85 ºС); λFe – beats heat of fusion of iron (λFe = 247.1 * 10 ^ 3 J / kg); qku – beats heat of combustion of coal (qku = 27 * 10 ^ 6 J / kg).

Data: ml – the mass of the taken iron scrap (ml = 10 ^ 3 kg); t0 – early. scrap temperature (t0 = 35 ºС); mku is the mass of coal (mku = 100 kg).

Let’s perform the calculation: ηset = ml * (CFe * (tpl – t0) + λFe) / (qku * mku) = 10 ^ 3 * (452 * (1538.85 – 35) + 247.1 * 10 ^ 3) / ( 27 * 10 ^ 6 * 100) = 0.343 or 34.3%.

Answer: The efficiency of the installation used is 34.3%.