Since the segment CM, by condition, is the median of the triangle ABC, then BM = AM = 3 cm, then the length of the side AB = AM + BM = 3 + 3 = 6 cm.
According to the condition, AH = CH = 2 cm, and then the height BH is also the height of the triangle, and therefore the triangle ABC is isosceles with the base AC.
Then AC = AH + CH = 2 + 2 = 4 cm, BC = AB = 6 cm.
Let’s define the perimeter of the triangle ABC.
Ravs = AB + BC + AC = 6 + 6 + 4 = 16 cm.
Answer: The perimeter of the triangle is 16 cm.
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