# Triangle ABC – rectangular, CB – 2, AC – 2√3. The bisector CK goes from corner C. Find the angle BKC.

August 31, 2021 | education

| Since the triangle ABC is rectangular, then tgBAC = BC / AC = 2/2 * √3 = 1 / √3.

Angle BAC = arctan (1 / √3) = 30.

Then the angle ABC = 90 – 30 = 60.

The segment CК is the bisector of the right angle, then the angle BСК = 90/2 = 45.

In the triangle BCК, the sum of the interior angles is 180, then the angle BСК = (180 – 45 – 60) = 75.

Answer: The ВKС angle is 75.

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