Since the triangle ABC is rectangular, then tgBAC = BC / AC = 2/2 * √3 = 1 / √3.
Angle BAC = arctan (1 / √3) = 30.
Then the angle ABC = 90 – 30 = 60.
The segment CК is the bisector of the right angle, then the angle BСК = 90/2 = 45.
In the triangle BCК, the sum of the interior angles is 180, then the angle BСК = (180 – 45 – 60) = 75.
Answer: The ВKС angle is 75.
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