Two alloys, of which the first contains 20% nickel and the second contains 40% nickel, were fused with each other, obtaining 180 kg of an alloy containing 25% nickel. How many kilograms was the mass of the first alloy?
Let’s denote the weight of the first alloy through x, then it contains (x * 0.2) kg of nickel (20%)
The weight of the second alloy will be (180 – x), and the nickel in it (180 – x) * 0.4 = 72 – 0.4 * x.
The mass of nickel in an alloy of two pieces is 180 * 0.25 = 45 kg.
Let’s make the equation:
0.2 * x +72 – 0.4 * x = 45;
0.2 * x = 27;
x = 135 kg.
Answer: The mass of the first ingot is 135 kg.
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