Two charges of 6 nC each are located at a distance of 100 cm from each other.

| September 27, 2021 | education

Two charges of 6 nC each are located at a distance of 100 cm from each other. What work must be done to bring them closer to a distance of 50 cm?

To find out the work done when the given charges approach each other, we use the formula: A12 = k * q1 * q2 / r1 – k * q1 * q ^ 2 / r2 = k * q2 * (1 / r1 – 1 / r2).

Const: k – coefficient of proportionality (k = 9 * 10 ^ 9 N * m2 / Kl2).

Data: q – the value of each charge (q = 6 nC = 6 * 10 ^ -9 C); r1 – initial distance between charges (r1 = 100 cm; in SI system r1 = 1 m); r2 is the considered distance between charges (r2 = 50 cm; in the SI system r2 = 0.5 m).

Let’s perform the calculation: A12 = k * q2 * (1 / r1 – 1 / r ^ 2) = 9 * 10 ^ 9 * (6 * 10 ^ -9) ^ 2 / (1/1 – 1 / 0.5) = -324 * 10 ^ -9 J.

Answer: The work done when the given charges approach each other is -324 nJ.



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