ro1 = 1000 kilograms per cubic meter – the density of water;
ro2 = 800 kilograms per cubic meter – kerosene density;
g = 10 Newtons per kilogram – acceleration of gravity (approximate value);
V1 = V2 = V – the volume of bodies is the same.
It is required to determine which body is affected by a large Archimedean force.
The first body immersed in water is acted upon by a buoyant (Archimedean) force equal to:
F1 = ro1 * g * V1 = ro1 * g * V = 1000 * 10 * V = 10000 * V.
The second body immersed in kerosene is acted upon by a buoyant (Archimedean) force equal to:
F2 = ro2 * g * V2 = ro2 * g * V = 800 * 10 * V = 8000 * V.
Since F1> F2 (10000 * V> 8000 * V), then a large Archimedean force acts on the first body (immersed in water).
Answer: a great Archimedean force acts on the first body (immersed in water).
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