Two identical bodies immersed one in water the other in kerosene. On which body does the great force of Archimedes act?

Given:

ro1 = 1000 kilograms per cubic meter – the density of water;

ro2 = 800 kilograms per cubic meter – kerosene density;

g = 10 Newtons per kilogram – acceleration of gravity (approximate value);

V1 = V2 = V – the volume of bodies is the same.

It is required to determine which body is affected by a large Archimedean force.

The first body immersed in water is acted upon by a buoyant (Archimedean) force equal to:

F1 = ro1 * g * V1 = ro1 * g * V = 1000 * 10 * V = 10000 * V.

The second body immersed in kerosene is acted upon by a buoyant (Archimedean) force equal to:

F2 = ro2 * g * V2 = ro2 * g * V = 800 * 10 * V = 8000 * V.

Since F1> F2 (10000 * V> 8000 * V), then a large Archimedean force acts on the first body (immersed in water).

Answer: a great Archimedean force acts on the first body (immersed in water).