Two lines intersect. Moreover, one of the corners is 40 less than the other. Find all the corners

In this case, you need to find the values of the adjacent angles.

Since one of them is 40º larger than the other, and their sum is equal to 180º, then we express:

x is the value of the angle ∠1;

x + 40 – the value of the angle ∠2;

x + x + 40 = 180;

x + x = 180 – 40;

2x = 140;

x = 140/2 = 70;

∠1 = 70º;

∠2 = 70º + 40º = 110º.

Answer: ∠1 = ∠3 = 70º, ∠2 = ∠4 = 110º.



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