# Two material points move in circles with radii R1 and R2, and R1 = 2R2. Provided that the linear velocities

**Two material points move in circles with radii R1 and R2, and R1 = 2R2. Provided that the linear velocities of the points are equal, their centripetal accelerations are related by the relationship 1. a1 = 2a22. a1 = a23. a1 = 0.5a24. a1 = 4a2**

R1 = 2 * R2.

V1 = V2.

a2 / a1 -?

With a uniform movement of a material point along a circle, as a result of a change in the direction of the linear velocity V, it has a centripetal acceleration a, which is always directed towards the center of the circle.

The centripetal acceleration a is determined by the formula: a = V ^ 2 / R, where R is the radius of curvature of the circle.

a1 = V1 ^ 2 / R1, a2 = V2 ^ 2 / R2.

Since by the condition of the problem R1 = 2 * R2 and V1 = V2, then a1 = V2 ^ 2/2 * R2.

a2 / a1 = 2 * R2 * V2 ^ 2 / V2 ^ 2 * R2 = 2.

a1 = a2 / 2 = 0.5 * a2.

Answer: the centripetal acceleration of the second body a2 is 2 times greater than the acceleration of the first body a1: a1 = 0.5 * a2.