# Two motorcyclists drove out of the two cities at the same time towards each other. One of them moved

Two motorcyclists drove out of the two cities at the same time towards each other. One of them moved at an average speed of 70 km / h and drove 140 km to the meeting, while the other moved at an average speed of 65 km / h. Find the distance between cities.

The speed of the 1st motorcyclist is 70 km / h;

The speed of the 2nd motorcyclist is 65 km / h;

Before meeting the 1st motorcyclist – 140 km;

Distance between cities – ? km.

S = V * t

Knowing that the first motorcyclist traveled 140 km at a speed of 70 km / h before the meeting, we find the travel time: t1 = S1: V1 = 140: 70 = 2 (h). Because the motorcyclists drove towards each other at the same time, which means they were on the way for the same time, i.e. t2 = 2 h.

Knowing the speed of the 2nd motorcyclist, let’s calculate the distance he traveled before the meeting:

S2 = V2 * t2 = 65 * 2 = 130 (km).

S total = S1 + S2 = 140 + 130 = 270 (km).

Answer: the distance between cities is 270 km.

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