# Two motorcyclists drove out of the two cities at the same time towards each other. One of them moved

**Two motorcyclists drove out of the two cities at the same time towards each other. One of them moved at an average speed of 70 km / h and drove 140 km to the meeting, while the other moved at an average speed of 65 km / h. Find the distance between cities.**

The speed of the 1st motorcyclist is 70 km / h;

The speed of the 2nd motorcyclist is 65 km / h;

Before meeting the 1st motorcyclist – 140 km;

Distance between cities – ? km.

S = V * t

Knowing that the first motorcyclist traveled 140 km at a speed of 70 km / h before the meeting, we find the travel time: t1 = S1: V1 = 140: 70 = 2 (h). Because the motorcyclists drove towards each other at the same time, which means they were on the way for the same time, i.e. t2 = 2 h.

Knowing the speed of the 2nd motorcyclist, let’s calculate the distance he traveled before the meeting:

S2 = V2 * t2 = 65 * 2 = 130 (km).

S total = S1 + S2 = 140 + 130 = 270 (km).

Answer: the distance between cities is 270 km.