Two pedestrians left points A and B at the same time to meet each other. They met 40 minutes after their exit

Two pedestrians left points A and B at the same time to meet each other. They met 40 minutes after their exit, and 32 minutes after the meeting, the first came to В. How many hours after leaving B, the second came to A?

We will solve this problem by actions.

1. Let’s find how long it took the first pedestrian to cover the distance between points A and B.

40 minutes + 32 minutes = 72 minutes.

2. Let us determine what part of the total travel time was spent by the first pedestrian on the way from point A to the meeting point.

40 minutes: 72 minutes = 5/9.

3. What part of the way did the first pedestrian go from point A to the meeting point?

5/9 way.

4. What part of the way did the second pedestrian go from point B to the meeting point?

1 – 5/9 = 4/9 paths.

5. Let’s find how many times the speed of the second pedestrian is less than the speed of the first pedestrian.

5/9; 4/9 = 5/4 times.

6. Let’s calculate how many hours after its exit from B the second came to A.

72 minutes * 5/4 = 90 minutes = 1.5 hours.

Answer: The second pedestrian came to A one and a half hours after leaving B.

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