Two people roll the dice once. The winner is the one who threw the most points. If the points are equally divided, then a draw ensues. A total of 9 points dropped out. Find the probability that Player One loses.
The sum of the points dropped out as a result of dice throws is an odd number, therefore, in this case, the players could not play a draw (a draw is possible only if the total number of points dropped out is even).
If we take into account that on the sides of a regular dice, from 1 to 6 points are indicated, then in order for the total to be 9 points, the first and second players could throw the following combinations of points: 3 and 6; 4 and 5; 5 and 4; 6 and 3.
So, there are two winning outcomes for the first player and two losing ones. Since the number of points on the dice is determined randomly, the probability of losing the first player is 0.5.
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