Two rectangles are given: the first one with sides 47 and 53 inches, the second with sides 358 cm and 695 cm. Which rectangle is larger and by how much?
Find the area of the first rectangle.
In the problem statement it is said that the width of the first rectangle is 47 dm, and the length of this rectangle is 53 dm, therefore, the area S1 of the first rectangle is:
S1 = 47 * 53 = 2491 dm ^ 2.
Let us express the lengths of the sides of the second rectangle in decimeters and find its area.
According to the condition of the problem, the lengths of the sides of the second rectangle are 358 cm and 695 cm.
Since there are 10 centimeters in one decimeter, the lengths of the sides of the second rectangle in decimeters are 358/10 = 35.8 dm and 695/10 = 69.5 dm, and its area S2 is:
S2 = 35.8 * 69.5 = 2488.1 dm ^ 2.
Therefore, the area of the second rectangle is larger by 2491 – 2488.1 = 2.9 dm ^ 2.
Answer: the area of the second rectangle is 2.9 dm ^ 2 larger.
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