Two rectangles have the same area. the length of one rectangle is 62 dm, and the width

Two rectangles have the same area. the length of one rectangle is 62 dm, and the width is 16 dm. find the length of another rectangle if its width is 31 cm.

First of all, we calculate the area of a rectangle, the length of which is 62 dm (620 cm), and the width is 16 dm (160 cm). To do this, we find the product of length and width:

S = 620 * 160 = 99200 (cm²).

By the condition of the problem, the area of this rectangle is equal to the area of another rectangle with a width of 31 cm.In order to calculate the unknown length, it is necessary to divide the area by the width:

99200: 31 = 3200 cm (320 dm).

Answer: the length of the other rectangle is 320 dm.