Two skaters are standing on smooth ice. The mass of one is 50 kg, the mass of the other is 25
| July 27, 2021 | education
Two skaters are standing on smooth ice. The mass of one is 50 kg, the mass of the other is 25. One skater pushed the other, and both rolled. Describe the movement of the skaters.
m1 = 50 kg.
m2 = 25 kg.
V2 / V1 -?
Impulse conservation law: m1 * V1 = m2 * V2.
V2 / V1 = m1 / m2.
V2 / V1 = 50 kg / 25 kg = 2.
The speed of a skater with a mass of 25 kg will be 2 times higher than the speed of a skater with a mass of 50 kg.
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