Two triangles are similar. The sides of one of them are equal to 10; 8; 12. The two sides of the second are 12 and 15. Find the third side of the second triangle.
In similar triangles, the ratios of the lengths of the similar sides are equal.
AC / A1C1 = 8/12 = 2/3.
ВС / В1С1 = 10/15 = 2/3.
AB / A1B1 = 2/3.
A1B1 = 3 * AB / 2 = 3 * 12/2 = 18 cm.
Answer: The length of the third side is 18 cm.
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