Two weights with masses of 1 kg and 2 kg are connected with a light rope evenly lifted. The mass of the upper load is 2 kg.

Two weights with masses of 1 kg and 2 kg are connected with a light rope evenly lifted. The mass of the upper load is 2 kg. In this case, the tension force of the rope between the weights is equal.

Given:

m1 = 2 kilograms – the mass of the top load;

m2 = 1 kilogram – weight of the bottom load;

g = 10 m / s2 – acceleration of gravity.

It is required to determine T (Newton) – the tension force of the rope between the weights.

Since in the condition of the problem it is said that the loads are lifted uniformly, we obtain 2 equations:

F – m1 * g – T = 0 (1);

T – m2 * g = 0 (2), where (1) is the equation of Newton’s second law for the upper load, (2) is the equation of Newton’s second law for the lower load, F is the force with which the loads are lifted.

From the second equation we find that:

T = m2 * g = 1 * 10 = 10 Newtons.

Answer: the rope pulling force is 10 Newton.




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