Two weights with masses of 1 kg and 2 kg are connected with a light rope evenly lifted. The mass of the upper load is 2 kg.
Two weights with masses of 1 kg and 2 kg are connected with a light rope evenly lifted. The mass of the upper load is 2 kg. In this case, the tension force of the rope between the weights is equal.
Given:
m1 = 2 kilograms – the mass of the top load;
m2 = 1 kilogram – weight of the bottom load;
g = 10 m / s2 – acceleration of gravity.
It is required to determine T (Newton) – the tension force of the rope between the weights.
Since in the condition of the problem it is said that the loads are lifted uniformly, we obtain 2 equations:
F – m1 * g – T = 0 (1);
T – m2 * g = 0 (2), where (1) is the equation of Newton’s second law for the upper load, (2) is the equation of Newton’s second law for the lower load, F is the force with which the loads are lifted.
From the second equation we find that:
T = m2 * g = 1 * 10 = 10 Newtons.
Answer: the rope pulling force is 10 Newton.