Under normal conditions, gas occupies a volume of 380 liters at what temperature, occupying

Under normal conditions, gas occupies a volume of 380 liters at what temperature, occupying a volume of 210 liters, will this gas create a pressure of 150 kPa? Determine the mass of the gas if its density under normal conditions is 0.09kg / m ^ 3

380 l = 0.38 m3;

210 l = 0.21 m3;

Let’s find the mass of the gas:

m (gas) = V (gas at normal conditions) * ρ (gas at normal conditions) = 0.38 * 0.09 = 0.0342 kg = 34.2 g;

Let’s find the amount of gas substance:

n (gas) = V (gas at n.o.) / VM = 380 / 22.4 = 16.96 mol;

Let us find the gas temperature after changing the conditions, expressing it from the Mendeleev-Clapeyron equation:

PV = nRT;

T = (PV) / (nR) = (150,000 * 0.21) / (16.96 * 8.314) = 223 K.

Answer: m (gas) = 34.2 g; T = 223 K.