Under normal conditions, how many liters of hydrogen are formed by the interaction of 4.6 grams of sodium with water?

2Na + 2H2O = 2NaOH + H2 – OBP, hydrogen is evolved;
Calculations by formulas:
M (Na) = 22.9 g / mol;

M (H2) = 2 g / mol;

Y (Na) = m / M = 4.6 / 22.9 = 0.2 mol.

Proportion:
0.2 mol (Na) – X mol (H2);

-2 mol -1 mol hence, X mol (H2) = 0.2 * 1/2 = 0.1 mol.

We find the volume of H2:
V (H2) = 0.1 * 22.4 = 2.24 L

Answer: hydrogen produced in a volume of 2.24 liters