Under normal conditions, how many liters of hydrogen are formed by the interaction of 4.6 grams of sodium with water?
July 28, 2021 | education|
2Na + 2H2O = 2NaOH + H2 – OBP, hydrogen is evolved;
Calculations by formulas:
M (Na) = 22.9 g / mol;
M (H2) = 2 g / mol;
Y (Na) = m / M = 4.6 / 22.9 = 0.2 mol.
0.2 mol (Na) – X mol (H2);
-2 mol -1 mol hence, X mol (H2) = 0.2 * 1/2 = 0.1 mol.
We find the volume of H2:
V (H2) = 0.1 * 22.4 = 2.24 L
Answer: hydrogen produced in a volume of 2.24 liters
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