Under what voltage is one of the sections of the TV with a resistance of 24 kOhm. If the current is 50 mA.

univerkov | March 26, 2021 | education

Initial data: R (resistance of the TV section) = 24 kOhm (24 * 10 ^ 3 Ohm); I (current in the section) = 50 mA (50 * 10 ^ -3 A).

The voltage under which one of the TV sections will be located is determined by the formula: U = I * R.

Calculation: U = 50 * 10 ^ -3 * 24 * 10 ^ 3 = 1200 V (1.2 kV).

Answer: One of the sections of the TV is powered by 1.2 kV.

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