Upon the interaction of 8.0 g of sulfur oxide (4), with an excess of potassium hydroxide solution

| September 28, 2021 | education

Upon the interaction of 8.0 g of sulfur oxide (4), with an excess of potassium hydroxide solution, 174 g of a solution of average salt were obtained. Calculate the mass fraction of salt in the resulting solution?

Find the amount of sulfur oxide (SO2) substance.

n = m: M.

M (SO2) = 32 + 32 = 64 g / mol.

n = 8 g: 64 g / mol = 0.125 mol.

Let’s compose the reaction equation:

2KOH + SO2 = K2SO3

According to the reaction equation, there is 1 mol of salt per 1 mole of sulfur oxide, that is, the substances are in quantitative ratios of 1: 1, which means their amount of substances will be the same.

n (SO2) = n (K2SO3) = 0.125 mol.

Find the mass of salt by the formula m = n × M,

M (K2SO3) = 39 × 2 + 32 + 16 × 3 = 158 g / mol.

m = 0.125 mol × 158 g / mol = 19.75 g.

W = m (substance): m (solution) × 100%,

W = (19.75g: 174g) × 100% = 11%.

Answer: 11%.



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