Using a lever, a load weighing 80 kg is lifted. How much force is applied to the long arm of the lever if its shoulders are at 2:16?
m = 80 kilograms – weight of the cargo;
x1 / x2 = 2/16 – the ratio of the lever arms;
g = 10 m / s ^ 2 – acceleration of gravity.
It is required to find the force F (Newton), which I apply to the long arm of the lever.
The force of gravity acts on the body, is equal to G = m * g. Then:
F * x2 = G * x1;
F * x2 = m * g * x1;
F = m * g * x1 / x2 = 80 * 10 * 2/16 = 1600/16 = 100 Newtons.
Answer: A force equal to 100 Newtons is applied to the long arm of the lever.
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