# Using the level of the chemical reaction C6H12O6-2C2H5OH + 2CO2, calculate the volume of carbon monoxide

**Using the level of the chemical reaction C6H12O6-2C2H5OH + 2CO2, calculate the volume of carbon monoxide released during alcoholic fermentation of glucose if 230 g of ethyl alcohol is obtained.**

Solution:

1. Determine the amount of ethanol, if its mass: m (C2H5OH) = 230g; M (C2H5OH) = 46 g / mol.

Y (C2H5OH) = m (C2H5OH) / M (C2H5OH): Y (C2H5OH) = 230/46 = 5 mol.

2. Taking into account the data on the reaction equation, we will compose the proportion:

X mol (C6H12O6) – 5 mol (C2H5OH)

X mol (C6H12O6) = 1 * 5/2 = 2.5 mol.

3. Determine the number of moles of CO2 based on the proportion:

2.5 mol (C6H12O6) – X mol (CO2)

X mol (CO2) = 2.5 * 2/1 = 5 mol.

4. Let’s calculate the volume of CO2 according to Avogadro’s law:

V (CO2) = 5 * 22.4 = 112 liters.

Answer: during alcoholic fermentation of glucose, 112 liters were released. carbon dioxide.