Water is poured into a cylindrical beaker up to a height of 60 cm. What is the pressure on the bottom of the beaker?

We translate the values ​​from given to the SI system:
h = 60 cm. = 0.6 m.
According to Pascal’s law:
The hydrostatic pressure inside the liquid at any depth does not depend on the shape of the vessel in which the liquid is located, and is equal to the product of the density of the liquid, the acceleration of gravity and the depth at which the pressure is determined:
P = ρ * g * h, where ρ is the density of the liquid, g is the free fall acceleration of a body raised above the Earth g = 9.8 m / s2, h is the depth of immersion in the liquid.
Using the reference book, we find the density of the liquid and substituting it into the formula, we find the pressure:
Water ρ = 1000 kg / m³
Substitute the numerical values ​​and determine the pressure of the liquid at the bottom:
P = ρ * g * h = 1000 * 9.8 * 0.6 = 5880 Pa.
Answer: The pressure at the bottom of the beaker is 5880 Pa or 5.88 kPa.




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