Water is poured into a vessel 15 cm high to a height of 7 cm, and benzite is poured on top of the water to the brim. Find the pressure on the bottom of the vessel.
h = 15 centimeters = 0.15 meters – the total height of a certain vessel;
h1 = 7 centimeters = 0.07 meters – the height of the water column in this vessel;
ro1 = 1000 kg / m3 (kilogram per cubic meter) – water density;
ro2 = 800 kg / m3 – gasoline density;
g = 9.8 N / kg (Newton per kilogram) – acceleration of gravity.
It is required to determine P (Pascal) – pressure at the bottom of the vessel.
The water pressure at the bottom of the vessel will be equal to:
P1 = ro1 * g * h1 = 1000 * 9.8 * 0.07 = 9800 * 0.07 = 686 Pascal.
The height of the column of gasoline in the vessel will be equal to:
h2 = h – h1 = 0.15 – 0.07 = 0.08 meters.
The gasoline pressure at the bottom will be equal to:
P2 = ro2 * g * h2 = 800 * 9.8 * 0.08 = 7840 * 0.08 = 627.2 Pascal.
The total pressure will be equal to:
P = P1 + P2 = 686 + 627.2 = 1313.2 Pascal.
Answer: the pressure on the bottom of the vessel will be equal to 1313.2 Pascal.