Water weighing 2.5 kg was heated by burning 14 g of gasoline for this. Find the final water temperature if its initial temperature is 18 degrees?
Initial data: m (mass of water) = 2.5 kg; m1 (mass of gasoline) = 14 g = 0.014 kg; t0 (initial water temperature) = 18 ºС.
Constants: C (specific heat capacity of water) = 4200 J / (kg * K); q (specific heat of combustion of gasoline) = 4.6 * 10 ^ 7 J / kg.
We find the final water temperature from the equality: C * m1 * (t – t0) = q * m2.
t – t0 = q * m2 / (C * m1) and t = q * m2 / (C * m1) + t0.
Let’s calculate: t = 4.6 * 10 ^ 7 * 0.014 / (4200 * 2.5) + 18 = 79.3 ºС.
Answer: The final water temperature will be 79.3 ºС.
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