We mixed hydrogen chloride with a mass of 7.3 g and ammonia with a mass of 4 g.

We mixed hydrogen chloride with a mass of 7.3 g and ammonia with a mass of 4 g. Determine the mass of the formed salt and the remaining salt after the reaction.

Given:
m (HCl) = 7.3 g
m (NH3) = 4 g

To find:
m (salt) -?
m (remainder) -?

Solution:
1) HCl + NH3 => NH4Cl;
2) n (HCl) = m (HCl) / M (HCl) = 7.3 / 36.5 = 0.2 mol;
3) n (NH3) = m (NH3) / M (NH3) = 4/17 = 0.24 mol;
4) n (NH4Cl) = n (HCl) = 0.2 mol;
5) m (NH4Cl) = n (NH4Cl) * M (NH4Cl) = 0.2 * 53.5 = 10.7 g;
6) n react. (NH3) = n (HCl) = 0.2 mol;
7) n rest. (NH3) = n (NH3) – n re. (NH3) = 0.24 – 0.2 = 0.04 mol;
8) m rest. (NH3) = n rest. (NH3) * M (NH3) = 0.04 * 17 = 0.68 g.

Answer: The mass of NH4Cl is 10.7 g; the remaining NH3 – 0.68 g.